Problems on Calendars Concept Part 2 - Concept of Identical ( Same) Calendars - Finding the day of the week on a particular date - Aptitude for CAT, Bank Tests, SSC, TCS NQT

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PROBLEMS ON CALENDARS - Concept Part 2


Finding the day of the week on a particular day when the reference date is given:

Calculate the "odd days" between the given and reference dates.

Exclude the reference day but include the target date in your calculation.

Example :

If January 1st, 2023 is a Sunday, March 14th, 2023 will be?

Reference Date: January 1, 2023 (Assume it's a Sunday)

Given Date: March 14, 2023

Number of days between the two dates :

Counting the number of days between January 1 and March 10 (excluding January 1):

Number of days=30(January)+28(February)+14(March)=72

Count the number of odd days :

The number of odd days in 72 days = 10 weeks + 2 extra days = 2 odd days

The target date (March 12) is after the reference date (January 1), so we are expecting a day "ahead" of the reference day.

Find the Day of the Week on the Target Date

Since there are 2 odd days, we count forward from Sunday:

Sunday + 2 = Tuesday

So, March 14th, 2023, falls on a Tuesday.

In summary, if January 1, 2023, is a Sunday, then March 14, 2023, is a Tuesday

 

Example 2 :

If July 1, 2024, is a Thursday, then 12th April 2024 is ?

Reference Date: July 1, 2024 (Assume it's a Thursday)

Target Date: April 12, 2024

 

Number of days between the two dates:

Counting the number of days between July 1 and April 12 (excluding July 1):

Number of days = 30 (June) + 31 (May) + 19 (April) = 80

 

Count the number of odd days:

The number of odd days in 80 days = 11 weeks and 3 days= 3 odd days

 

Find the Day of the Week on the Target Date:

Since there are 3 odd days, we count backward from Thursday:

Thursday - 3 = Monday

 

So, May 12th, 2024, falls on a Monday.

 

Predicting Identical Calendars in Different Years(Repetition of the calendar )


For any ( leap year + 1) year :

Let us take an example, 2005

Year                       2005      2006        2007    2008      2009   2010

Odd days                  1            1             1          2            1         1

Since the number of odd days is 7, so calendars of 2005 and 2011 will be the same for the whole year.

Any (leap year  +1), the same calendar will occur after 6 years.    

2005 + 6 =2011

For any ( leap year + 2) year :

Let us take an example, 2006

Year                 2006  2007 2008  2009   2010  2011 2012  2013  2014  2015  2016 

Odd days            1        1       2       1        1        1        2        1      1       1              2

 

Since the number of odd days is 14 (i.e. 0), so calendars of 2006 and 2017 will be the same.

Any ( leap year  + 2), the same calendar will occur after 11 years.    

2006 + 11 =2017

For any ( leap year + 3) year :

Let us take an example, 2007

Year               2007    2008   2009   2010  2011 2012   2013  2014  2015  2016 2017 

Odd days          1         2        1         1         1      2         1        1        1      2       1

 

Since the number of odd days is 14, so calendars of 2007 and 2018 will be the same for the whole year.

Any ( leap year  +3), the same calendar will occur after 11 years.    

2007 + 11 =2018

Same calendar for a leap Year :

 

The calendar of a leap year repeats itself after 28 years.

So, to find the year with the same calendar as a given leap year, simply add 28 to that year.

For example, the calendar of 2004 is the same as the calendar of 2004 + 28 = 2032.

The same Calendars of months in a year

Leap Year:  January & July, February & August.

Non-Leap Year: January & October, February & March

Any year, leap or non leap year: March & November, April & July, September & December

Finding the day of the week on a particular date:

How to find the day of the week on a given date :

To find the day of the week on a date, we need to find odd days right from the 1st January 1 A.D. to the date given. We add up the odd days of the complete centuries, the completed years of the present century and the completed quarters, the completed months of the current quarter, and the number of days of the current month.

Example: Find out the day of the week on November 8th, 2015.

Explanation:

Period                                                                     Number of odd days

 First 2000 years                (5 x 400 years)                             0

14 years                           (3 leap+11 normal years)               17

2015. First quarter             Jan, Feb, Mar                                 6

2015, 2nd quarter                Apr, May, June                              0

2015, Third quarter             July, Aug, September                     1

2015 October 31 days                                                             3

 

2015 November        up to 8th                                                 1

-------------------------------------------------------------------------------------

Total                                                                                    28

NUMBER OF ODD DAYS                                                           0

 

Number of odd days =0

This means that the day of the week on November 8th is Sunday.

  

Number of odd days                                   Day of the week

0                                                              Sunday

1                                                              Monday

2                                                              Tuesday

3                                                              Wednesday

4                                                              Thursday

5                                                              Friday

6                                                              Saturday

 

Important Points :

1.     The last day of a century cannot be either a  Tuesday, Thursday, or Saturday.

2.    The first day of the century cannot be either Wednesday, Friday, or Sunday

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